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HomeNotesClass 9PhysicsGravitation
Chapter 3 · Class 9 · Physics · CBSE/NCERT

Gravitation

From the Chandrayaan missions to ships floating in the Arabian Sea, gravitation governs motion across the universe. This chapter covers universal gravitation, free fall, mass and weight, pressure, buoyancy, Archimedes' principle, and flotation.

GravitationFree FallMass & WeightPressureBuoyancyArchimedesFlotation
Complete Chapter Roadmap — 11 Topics
1

Universal Law of Gravitation

Every mass attracts every other mass in the universe

Formula
F=Gm1m2r2F = G\frac{m_1 m_2}{r^2}

where GG is the gravitational constant, m1m_1 and m2m_2 are masses, and rr is the distance between their centres.
Every object in the universe attracts every other object with a gravitational force. The force is attractive and acts along the line joining the two objects.
Newton's universal law of gravitation states that the gravitational force between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centres.
This means if you double the mass of one body, the force doubles. But if you double the distance between them, the force becomes one-fourth. This inverse-square relationship is important and comes up in many exam questions.
2

Gravitational Constant G

A universal constant that applies everywhere

Key Distinction
Do not confuse G (universal gravitational constant, fixed everywhere) with g (acceleration due to gravity, which varies from place to place).
The gravitational constant G has a fixed value everywhere in the universe:
G=6.674×1011 N m2 kg2G = 6.674 \times 10^{-11}\ \text{N m}^2\ \text{kg}^{-2}
G is a universal constant, meaning its value is the same on Earth, on the Moon, and anywhere else in space. It was first measured experimentally by Henry Cavendish.
Because G is extremely small, gravitational force between ordinary objects of everyday mass is negligibly tiny. Gravitational effects are noticeable only when at least one of the masses is very large, such as a planet or a star.
3

Free Fall and Acceleration due to Gravity

All objects fall at the same rate in vacuum

Value to Remember
g9.8 m/s2g \approx 9.8\ \text{m/s}^2
on Earth's surface (often rounded to 10 m/s² in CBSE calculations).
When an object moves under the influence of gravity alone, with no other force acting on it, it is said to be in free fall. A freely falling body accelerates toward the Earth at a rate called the acceleration due to gravity, denoted g.
Near the Earth's surface, g is approximately 9.8 m/s². This means a freely falling body gains 9.8 m/s of speed every second.
A remarkable fact shown by Galileo and confirmed in vacuum experiments is that all freely falling bodies experience the same acceleration regardless of their mass. A heavy iron ball and a light feather dropped together in vacuum reach the ground at exactly the same time.
In normal conditions, air resistance affects light objects more than heavy ones. That is why a feather falls slower than a coin when dropped from the rooftop of a building in a Delhi neighbourhood.
Quick Check
An object is dropped from rest. How fast is it moving after 3 seconds?

Answer: v=u+gt=0+9.8×3=29.4v = u + gt = 0 + 9.8 \times 3 = 29.4 m/s.
4

Equations of Motion Under Gravity

The three motion equations applied to falling bodies

Equations for Free Fall
v=u+gtv = u + gt

h=ut+12gt2h = ut + \tfrac{1}{2}gt^2

v2=u2+2ghv^2 = u^2 + 2gh

For a body dropped from rest:
u=0u = 0
The same three equations of motion from Chapter 1 apply to free fall, with acceleration replaced by g for downward motion and −g for upward motion.
When a ball is thrown upward from a terrace in Jaipur, it decelerates at 9.8 m/s² going up and accelerates at 9.8 m/s² coming down. At the highest point, velocity is zero but acceleration is still g downward.
Solved Example

Object dropped from a building

A stone is dropped from the top of a 20 m building. Find the velocity when it hits the ground (g = 10 m/s²).

Using v2=u2+2ghv^2 = u^2 + 2gh with u=0u = 0:
v2=0+2×10×20=400v^2 = 0 + 2 \times 10 \times 20 = 400

v=20 m/sv = 20\ \text{m/s}
Show a ball-thrown-upward problem

A ball is thrown upward at 20 m/s. Find the maximum height (g = 10 m/s²).

At maximum height, v=0v = 0. Using v2=u22ghv^2 = u^2 - 2gh:

0=4002×10×h0 = 400 - 2 \times 10 \times h, so h=20h = 20 m.

5

Mass and Weight

Mass stays constant; weight changes with gravity

Formula
W=mgW = mg

Weight is measured in newtons (N) and mass in kilograms (kg).
Mass is the amount of matter in a body. It is a scalar quantity measured in kilograms. Mass stays the same everywhere — on the Earth, on the Moon, or in deep space.
Weight is the gravitational force exerted by the Earth (or any other body) on an object. Since it is a force, weight is measured in newtons. Weight depends on the value of g at the location.
A student who has a mass of 60 kg has the same mass everywhere. But the student's weight on Earth is about 588 N, while on the Moon it would be only about 98 N because the Moon's gravity is weaker.
Solved Example

Weight on Earth

Find the weight of a 50 kg student on Earth (g = 9.8 m/s²).

W=mg=50×9.8=490 NW = mg = 50 \times 9.8 = 490\ \text{N}
6

Weight on the Moon

Why astronauts weigh less on the Moon

Quick Rule
Weight on the Moon ≈ Weight on Earth ÷ 6, because gmoongearth/6g_{moon} \approx g_{earth}/6.
The Moon has much less mass than the Earth, so its gravitational pull is weaker. The acceleration due to gravity on the Moon is about
gmoon1.63 m/s2g_{moon} \approx 1.63\ \text{m/s}^2
which is roughly one-sixth of g on Earth.
ISRO scientists working on Chandrayaan missions carefully account for this difference when designing landers and rovers. Instruments, equipment, and mobility systems must work correctly under the Moon's weaker gravity.
An astronaut who weighs 600 N on Earth weighs only about 100 N on the Moon. This makes movement feel much lighter and jumping much easier. Mass, however, remains unchanged at 60 kg.
Quick Practice
A person weighs 540 N on Earth. Find the weight on the Moon.

Answer: Weight on Moon =540/6=90= 540/6 = 90 N.
7

Thrust and Pressure

The same force on a smaller area creates higher pressure

Formula
P=FAP = \frac{F}{A}

where PP is pressure in pascals (Pa), FF is thrust in newtons, and AA is area in m².
Thrust is the force acting perpendicular to a surface. Pressure is the thrust per unit area. The same thrust creates higher pressure on a smaller area.
A sharp knife cuts vegetables more easily than a blunt one because the same force from your hand is concentrated on a much smaller area at the sharp edge, creating greater pressure on the vegetable.
Tractors used in farms in Punjab and Haryana have wide tyres so that the weight of the tractor spreads over a large area, reducing pressure on soft soil and preventing the tractor from sinking.
Solved Example

Pressure under a stiletto heel

A force of 600 N acts on an area of 0.003 m². Find the pressure.

P=6000.003=200,000 Pa=2×105 PaP = \frac{600}{0.003} = 200{,}000\ \text{Pa} = 2 \times 10^5\ \text{Pa}
8

Buoyancy

Fluids exert an upward force on immersed objects

Key Idea
Buoyant force = weight of fluid displaced by the object. The more fluid an object displaces, the greater the upward push on it.
When an object is immersed in a fluid (liquid or gas), the fluid exerts a pressure on all surfaces of the object. Because pressure increases with depth, the upward pressure on the bottom of the object is greater than the downward pressure on the top. This net upward force is called buoyant force or upthrust.
You can easily feel this force when you try to push a rubber ball or an inflated balloon into a bucket of water — the water pushes back upward. Children playing in a swimming pool or a river experience buoyancy as a lifting sensation in water.
Buoyant force depends on the volume of fluid displaced and the density of the fluid. It does not depend on the mass or density of the object itself.
9

Archimedes' Principle

Upthrust equals weight of displaced fluid

Formula
Fbuoyant=ρfluid×Vdisplaced×gF_{buoyant} = \rho_{fluid} \times V_{displaced} \times g

where ρfluid\rho_{fluid} is the density of the fluid and VdisplacedV_{displaced} is the volume of fluid displaced.
Archimedes' principle states that a body wholly or partially immersed in a fluid experiences an upward buoyant force equal to the weight of the fluid displaced by it.
This principle allows us to measure buoyant force precisely. If an object displaces 500 mL of water, the buoyant force on it equals the weight of 500 mL of water, which is about 4.9 N.
Archimedes' principle has many practical applications in India. Ships carrying cargo from Mumbai and Chennai ports are designed so that the weight of water they displace equals the total weight of the ship and cargo. Hydrometer instruments used in dairy farms to check the purity of milk also use this principle.
Think About It
An object appears to weigh 50 N in air but only 40 N when submerged in water. What is the buoyant force?

Answer: Buoyant force = 50 − 40 = 10 N. This equals the weight of water displaced by the object.
10

Flotation and Relative Density

Why some objects float and others sink

An object floats when the buoyant force acting on it equals its weight. This happens when the average density of the object is less than or equal to the density of the fluid.
An iron nail sinks in water because the volume of water it displaces weighs less than the nail itself. But a large steel ship shaped like a hollow bowl displaces a huge volume of water whose weight can equal the entire weight of the ship and cargo, so it floats. This is why ships made of steel float even though steel is denser than water.
Relative density (also called specific gravity) is the ratio of the density of a substance to the density of water at 4 °C. If relative density is less than 1, the substance floats in water. Wood, cork, and ice have relative density less than 1. Iron, copper, and stone have relative density greater than 1.
Real-World Example

Earthen matka and submarine

An earthen matka (clay pot) floats when empty but sinks when filled with water, because filling it reduces the air volume inside and increases total weight beyond the buoyant force.

A submarine adjusts the amount of water in its ballast tanks to control whether it floats or sinks, using the same flotation principle.
11

Complete Chapter Summary

Key laws, formulas, and ideas to revise before exams

Universal gravitation:
F=Gm1m2/r2F = G m_1 m_2 / r^2
. G is universal; g varies by location.
Free fall: all bodies fall with same acceleration g ≈ 9.8 m/s² in vacuum.
Weight:
W=mgW = mg
. Weight on Moon ≈ Weight on Earth ÷ 6.
Pressure:
P=F/AP = F/A
. More area → less pressure; less area → more pressure.
Archimedes' principle: buoyant force = weight of fluid displaced.
Flotation: object floats when density ≤ density of fluid.
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