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Chapter 2 | Class 10 | CBSE / NCERT

Polynomials

Complete Class 10 revision notes for degree, zeros, graphs, coefficient relations, and the division algorithm.

Chapter Roadmap
1

What is a Polynomial?

An algebraic expression with whole-number powers of the variable

Not a Polynomial
  • 1x=x1\frac{1}{x}=x^{-1}
  • x=x1/2\sqrt{x}=x^{1/2}
  • 2x2^x
A polynomial is built from terms like 5x25x^2, 3x3x, and constants such as 2.
The power of the variable must be a non-negative integer. So negative powers, fractional powers, and variables in the exponent are not allowed.
Key Formulas
f(x)=anxn+an1xn1++a1x+a0f(x)=a_nx^n+a_{n-1}x^{n-1}+\cdots+a_1x+a_0
All powers of the variable must be non-negative integers.
Practice
Which are polynomials: 3x22x+13x^2-2x+1, x+1xx+\frac{1}{x}, 2x5\sqrt{2}x-5, x1/3+4x^{1/3}+4?

Answer: The first and third.
2

Degree of a Polynomial

The highest power gives the degree

Examples
  • 2x32x-3 has degree 1
  • 3x2+x43x^2+x-4 has degree 2
  • 2x35x2+x2x^3-5x^2+x has degree 3
The degree is the highest power of the variable with a non-zero coefficient.
A non-zero constant has degree 0, while the zero polynomial has no defined degree.
Practice
Find the degree of 5x33x2+115x^3-3x^2+11, 7y432y7y^4-\frac{3}{2}y, and 1313.
3

Types of Polynomials

Classification by degree and number of terms

Degree 0 is constant, degree 1 is linear, degree 2 is quadratic, and degree 3 is cubic.
By terms: monomial means 1 term, binomial means 2 terms, and trinomial means 3 terms.
Key Formulas
ax+bax+b
Linear polynomial
ax2+bx+cax^2+bx+c
Quadratic polynomial
ax3+bx2+cx+dax^3+bx^2+cx+d
Cubic polynomial
Practice
Classify x34xx^3-4x, 77, and 4x25x+34x^2-5x+3.
4

Value of a Polynomial

Substitute the given value of the variable

To find f(a)f(a), replace every xx with aa and simplify.
This is called evaluating the polynomial at a point.
Worked Example

Evaluate a cubic

For f(x)=2x313x2+17x+12f(x)=2x^3-13x^2+17x+12, find f(1)f(1) and f(2)f(-2).
Show solution

f(1)=213+17+12=18f(1)=2-13+17+12=18

f(2)=165234+12=90f(-2)=-16-52-34+12=-90

Practice
If p(x)=x33x2+2x6p(x)=x^3-3x^2+2x-6, find p(0)p(0) and p(2)p(2).
5

Zero of a Polynomial

A value that makes the polynomial equal to zero

A real number α\alpha is a zero of f(x)f(x) if f(α)=0f(\alpha)=0.
A polynomial of degree nn can have at most nn zeros.
Key Formulas
f(α)=0f(\alpha)=0
If this happens, then \alpha is a zero of f(x).
Practice
Find the zero of 2x62x-6.

Answer: x=3x=3.
6

Graph of a Linear Polynomial

A straight line with one x-intercept

The graph of f(x)=ax+bf(x)=ax+b is a straight line.
Its zero is where the line cuts the x-axis.
Key Formulas
Zero=ba\text{Zero}=-\frac{b}{a}
The x-intercept of a line y=ax+b.
Graph of y = 2x - 5
-112345-7-6-5-4-3-2-112345(1,-3)(4,3)(2.5,0)y = 2x - 5xy

A linear polynomial is always a straight line, and its zero is the single x-intercept.

Worked Example

Linear graph

For f(x)=2x5f(x)=2x-5, find the zero.
Show solution

Set 2x5=02x-5=0.

So x=52x=\frac{5}{2}.

Practice
Find the zero of 3x93x-9.
7

Graph of a Quadratic Polynomial

A parabola that opens up or down

The graph of ax2+bx+cax^2+bx+c is a parabola.
If a>0a>0, it opens upward. If a<0a<0, it opens downward.
Key Formulas
xvertex=b2ax_{\text{vertex}}=-\frac{b}{2a}
x-coordinate of the turning point
D=b24acD=b^2-4ac
The discriminant decides the number of real zeros
Graph of y = x² - 2x - 8
-4-3-2-1123456-10-9-8-7-6-5-4-3-2-112345678(-2,0)(4,0)(1,-9)y = x² - 2x - 8xy

This parabola opens upward, has vertex (1,-9), and crosses the x-axis at -2 and 4.

Practice
For x2+2x+3-x^2+2x+3, state the opening direction and find the zeros.
8

Three Cases of the Parabola

The discriminant tells the number of real zeros

Cases
  • D>0D>0: two distinct real zeros
  • D=0D=0: one repeated real zero
  • D<0D<0: no real zero
For a quadratic, the discriminant is D=b24acD=b^2-4ac.
It tells whether the parabola cuts, touches, or misses the x-axis.
D > 0
12345-1123456723Vy = x² - 5x + 6xy

Two distinct real zeros

D = 0
123456-11234567(3,0)y = (x - 3)²xy

One repeated real zero

D < 0
-3-2-112-1123456Vy = x² + x + 1xy

No real zeros

Practice
Compute DD for x2+4x+4x^2+4x+4, x2+1x^2+1, and x25x+6x^2-5x+6.
9

Graph of a Cubic Polynomial

An S-shaped graph with at least one real zero

A cubic polynomial may cut the x-axis 1, 2, or 3 times.
It always has at least one real zero.
Three Zeros
-3-2-1123-15-14-13-12-11-10-9-8-7-6-5-4-3-2-1123456789101112131415-202y = x³ - 4xxy

x³ - 4x crosses the x-axis three times

Double Zero + Simple Zero
-1123-4-3-2-1123456702y = x³ - 2x²xy

x³ - 2x² touches at 0 and crosses at 2

One Zero
-2-112-10-9-8-7-6-5-4-3-2-112345678910(0,0)y = x³xy

x³ has one real zero at the origin

Worked Example

Factor and read the graph

Find the zeros of x34xx^3-4x.
Show solution

x34x=x(x24)=x(x2)(x+2)x^3-4x=x(x^2-4)=x(x-2)(x+2)

Zeros are 2-2, 0, and 2.

Practice
Find the zeros of x33x2+2xx^3-3x^2+2x.
10

Geometrical Meaning of Zeros

Zeros are x-intercepts of the graph

The zeros of f(x)f(x) are the x-coordinates of the points where the graph y=f(x)y=f(x) meets the x-axis.
So a graph gives a direct visual meaning to zeros.
Key Formulas
Zeros of f(x)=x-coordinates where y=f(x) meets the x-axis\text{Zeros of }f(x)=\text{x-coordinates where }y=f(x)\text{ meets the x-axis}
Zeros From the Graph
-5-4-3-2-112345-4-3-2-11234x = ax = bx = cy = f(x)xy

The x-coordinates where the curve meets the x-axis are the zeros of the polynomial.

11

Zeros and Coefficients of a Quadratic Polynomial

Useful relations for sum and product of zeros

If ax2+bx+cax^2+bx+c has zeros α\alpha and β\beta, then we can write direct relations using coefficients.
Key Formulas
α+β=ba\alpha+\beta=-\frac{b}{a}
Sum of zeros
αβ=ca\alpha\beta=\frac{c}{a}
Product of zeros
Worked Example

Verify a relation

For x2+7x+12x^2+7x+12, find the zeros and verify the relations.
Show solution

x2+7x+12=(x+4)(x+3)x^2+7x+12=(x+4)(x+3), so zeros are 4-4 and 3-3.

Sum =7=-7 and product =12=12, matching the formulas.

12

Zeros and Coefficients of a Cubic Polynomial

Three standard relations for three zeros

For ax3+bx2+cx+dax^3+bx^2+cx+d with zeros α\alpha, β\beta, and γ\gamma, three symmetric relations are used.
Key Formulas
α+β+γ=ba\alpha+\beta+\gamma=-\frac{b}{a}
Sum of three zeros
αβ+βγ+γα=ca\alpha\beta+\beta\gamma+\gamma\alpha=\frac{c}{a}
Sum of pairwise products
αβγ=da\alpha\beta\gamma=-\frac{d}{a}
Product of all three zeros
13

Finding a Polynomial from Its Zeros

Build the polynomial in reverse

If the zeros are known, a polynomial can be constructed from them.
For a quadratic with zeros α\alpha and β\beta, use the sum and product form.
Key Formulas
f(x)=k(x2(α+β)x+αβ)f(x)=k\left(x^2-(\alpha+\beta)x+\alpha\beta\right)
Use the given zeros to build a quadratic polynomial.
Practice
Find a quadratic polynomial with zeros 14\frac{1}{4} and 1-1.

Answer: One such polynomial is 4x2+3x14x^2+3x-1.
14

Division Algorithm

Divide one polynomial by another

For polynomials f(x)f(x) and g(x)g(x) with g(x)0g(x)\neq 0, division gives a quotient and remainder.
The remainder must have smaller degree than the divisor.
Key Formulas
f(x)=g(x)q(x)+r(x)f(x)=g(x)q(x)+r(x)
Dividend = Divisor x Quotient + Remainder
deg(r)<deg(g)\deg(r)<\deg(g)
Remainder must have smaller degree than divisor
Worked Example

Polynomial division

Divide 6x3+11x239x656x^3+11x^2-39x-65 by x2+x5x^2+x-5.
Show solution

The quotient is 6x+56x+5 and the remainder is 14x40-14x-40.

Practice
Divide x33x2+5x3x^3-3x^2+5x-3 by x22x^2-2.

Answer: Quotient =x3=x-3, remainder =7x9=7x-9.

Quick Summary

ConceptKey Idea
Polynomial
Only non-negative integral powers of the variable
Degree
Highest power of the variable
Zero
f(α)=0f(\alpha)=0
Linear
Straight line, one zero
Quadratic
Parabola, up to two real zeros
Cubic
At least one real zero, at most three
Quadratic relation
α+β=ba\alpha+\beta=-\frac{b}{a} and αβ=ca\alpha\beta=\frac{c}{a}
Division algorithm
f(x)=g(x)q(x)+r(x)f(x)=g(x)q(x)+r(x)
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