CUET UG / Quantitative Aptitude / Number System

Number System Notes for CUET UG

Learn Number System from the ground up with original notes, logic-first shortcuts, 30+ solved examples, exam traps, and a separate timed practice route built for CUET UG aspirants who want speed and clarity.

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Why Number System Matters in CUET UG

Number System is one of the most scoring and most misunderstood areas in quantitative aptitude. Many students memorise divisibility rules or remainder tricks without understanding the logic behind them. That becomes a problem the moment the examiner twists a familiar pattern. CUET UG questions on Number System are rarely about raw calculation alone. They reward pattern recognition, quick classification, and the confidence to reduce a large-looking expression into a smaller idea.

Think of a student spotting a giant power such as 7^103. A weak approach is to panic because the expression looks large. A strong approach is to ask whether the full value is needed or only the unit digit. That change in thinking is exactly what this module is designed to teach.

The chapter also acts like a base layer for the rest of arithmetic aptitude. Once you understand divisibility, factors, parity, powers, remainders, and digit cycles, questions from simplification, algebra, HCF-LCM, and even data-based shortcuts become easier to decode.

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Section A

Number System Notes and Core Concepts

Original teaching copy for Learn at My Place

1. Real Numbers and Number Types

Number System is the language of arithmetic. Before a student solves percentages, averages, algebraic simplification, or quantitative aptitude puzzles, the student has to understand how numbers behave. That is why Number System is treated as a foundational topic in almost every aptitude book. In CUET UG, this chapter looks simple on the surface, but it quietly powers many other questions based on divisibility, factors, remainders, and pattern recognition.

Real numbers are all the numbers that can be shown on the number line. This includes positive numbers, negative numbers, fractions, decimals, surds such as 2\sqrt{2}, and constants like π\pi.

Real Numbers=Rational NumbersIrrational Numbers\text{Real Numbers} = \text{Rational Numbers} \cup \text{Irrational Numbers}

Natural numbers start from 1. Whole numbers include 0. Integers include negative numbers as well. A quick way to remember the hierarchy is to think in layers: natural numbers are inside whole numbers, and whole numbers are inside integers.

Natural Numbers={1,2,3,4,}\text{Natural Numbers} = \{1,2,3,4,\dots\}
Whole Numbers={0,1,2,3,4,}\text{Whole Numbers} = \{0,1,2,3,4,\dots\}
Integers={,3,2,1,0,1,2,3,}\text{Integers} = \{\dots,-3,-2,-1,0,1,2,3,\dots\}

This matters in MCQs because examiners often hide small classification traps. If 0 is present, think about whole numbers. If negatives are present, think about integers. If a number has a non-terminating and non-repeating decimal expansion, it is irrational.

Rational numbers can always be written as p/qp/q where q0q \ne 0. That means integers, proper fractions, improper fractions, terminating decimals, and repeating decimals are all rational numbers. For example, 0.125 is rational because it can be written as 1/81/8, and 0.30.\overline{3} is rational because it equals 1/31/3.

10-second shortcut: Terminating decimal or repeating decimal means rational. Non-terminating and non-repeating means irrational.

2. Even, Odd, Prime, and Composite Logic

Even and odd behaviour shows up in many fast CUET questions where full calculation is unnecessary. An even number is divisible by 2. An odd number is not divisible by 2. The algebraic forms below are extremely useful because they let us prove parity rules in seconds.

Even Numbers=2n,Odd Numbers=2n+1\text{Even Numbers} = 2n, \quad \text{Odd Numbers} = 2n+1

Key parity rules are easy to remember but even more useful when you apply them before calculating. Even + Even = Even, Odd + Odd = Even, Even + Odd = Odd, Even multiplied by anything stays even, and Odd multiplied by Odd stays odd.

Prime and composite numbers create another classic CUET trap. A prime number has exactly two distinct positive factors: 1 and itself. A composite number has more than two positive factors. The number 2 is special because it is the only even prime number. The number 1 is neither prime nor composite because it has only one positive factor.

Students often mark 1 as prime out of habit. That mistake can ruin factor-counting or prime-list questions. Another useful insight is that to test whether a number is prime, it is enough to check divisibility by primes up to its square root.

Exam insight: If a question asks for the smallest prime number, the answer is 2. If it asks for the smallest composite number, the answer is 4.

For example, if Arjun is checking whether 97 is prime, he only needs to test divisibility by 2, 3, 5, and 7 because 97\sqrt{97} is less than 10. Since none of those primes divides 97, the number is prime.

3. Fractions, Decimals, and Number Line Ordering

Fractions are rational numbers written as p/qp/q. They are typically classified as proper fractions, improper fractions, and mixed fractions. CUET questions may not ask these names directly, but understanding them helps in approximation and comparison questions.

A proper fraction has numerator smaller than denominator, such as 3/73/7. An improper fraction has numerator greater than or equal to denominator, such as 9/49/4. A mixed fraction combines an integer and a proper fraction, such as 2132\frac{1}{3}.

Decimal conversions also save time. Students should know the common ones instantly: 1/2=0.51/2 = 0.5, 1/4=0.251/4 = 0.25, 3/4=0.753/4 = 0.75, 1/5=0.21/5 = 0.2, and 1/8=0.1251/8 = 0.125.

12=0.5,14=0.25,34=0.75,15=0.2\frac{1}{2}=0.5, \quad \frac{1}{4}=0.25, \quad \frac{3}{4}=0.75, \quad \frac{1}{5}=0.2

Number line sense is another underestimated skill. On the number line, numbers increase as we move to the right. This becomes crucial when comparing negative numbers. Between -3 and -8, the greater number is -3 because it lies closer to zero and further to the right.

Exam trap: Students often think 8 is bigger than 3, so -8 must be bigger than -3. That is false. Among negative numbers, the number closer to zero is greater.

If Priya learns to use the number line mentally, many sign-based questions become immediate and she avoids avoidable mistakes in integer comparison.

4. Factors, Multiples, and Prime Factorisation

A factor of a number divides it exactly. A multiple of a number is obtained by multiplying it with integers. This sounds basic, but factor-multiple confusion is one of the most common student errors in objective exams.

For 12, the factors are 1, 2, 3, 4, 6, and 12. The multiples are 12, 24, 36, 48, and so on. A factor is always less than or equal to the number. A multiple can be equal to or greater than the number. Every number has finitely many factors but infinitely many multiples.

Prime factorisation is the key that unlocks many problems in Number System. Every composite number can be expressed uniquely as a product of prime numbers.

360=23×32×5360 = 2^3 \times 3^2 \times 5

Once prime factorisation is done, factor-counting becomes straightforward. If a number is written as N=paqbrcN = p^a q^b r^c, then the number of positive factors is (a+1)(b+1)(c+1)(a+1)(b+1)(c+1).

If N=paqbrc,number of factors=(a+1)(b+1)(c+1)\text{If } N = p^a q^b r^c, \quad \text{number of factors} = (a+1)(b+1)(c+1)

For example, 72=23×3272 = 2^3 \times 3^2, so the number of positive factors is (3+1)(2+1)=12(3+1)(2+1)=12.

This chapter also supports HCF-LCM style thinking, because once numbers are expressed in prime powers, it becomes much easier to identify common and uncommon prime exponents.

10-second shortcut: If a question asks how many factors a number has, factorise first. Do not start listing factors unless the number is very small.

5. Divisibility Rules with Logic

Divisibility rules are among the fastest scoring tools in CUET UG, but they are most powerful when students understand why they work. That understanding prevents panic when the examiner twists a familiar-looking problem.

A number is divisible by 2 if its last digit is 0, 2, 4, 6, or 8. A number is divisible by 5 if its last digit is 0 or 5. These work because every higher power of 10 is already divisible by 2 and 5, so only the last digit matters.

A number is divisible by 4 if its last two digits form a number divisible by 4, and divisible by 8 if its last three digits form a number divisible by 8. This happens because 100 is divisible by 4 and 1000 is divisible by 8.

Divisibility by 3 and 9 comes from place value and modular thinking. Since 101(mod3)10 \equiv 1 \pmod 3 and 101(mod9)10 \equiv 1 \pmod 9, a number behaves like the sum of its digits when tested against 3 or 9.

564=5×100+6×10+4564 = 5 \times 100 + 6 \times 10 + 4
1001(mod3),101(mod3)100 \equiv 1 \pmod 3, \quad 10 \equiv 1 \pmod 3
5645+6+4=15(mod3)564 \equiv 5 + 6 + 4 = 15 \pmod 3

That is why 564 is divisible by 3 exactly when 15 is divisible by 3.

A number is divisible by 6 if and only if it is divisible by both 2 and 3. The divisibility rule of 11 is based on the identity 101(mod11)10 \equiv -1 \pmod{11}, which makes powers of 10 alternate between +1 and -1. That is why the difference between alternate digit sums decides divisibility by 11.

101(mod11)10 \equiv -1 \pmod{11}
5372453+72+4=1153724 \Rightarrow 5 - 3 + 7 - 2 + 4 = 11
Why the rule of 11 works: alternate place values act like +1 and -1 modulo 11, so the number collapses into an alternating digit sum.

Once students understand this, the rule feels logical rather than magical.

6. Remainders, Cyclicity, and Unit Digits

Remainders are one of the most exam-relevant parts of Number System. If a number aa is divided by bb, then it can always be written as a=bq+ra = bq + r, where the remainder satisfies 0r<b0 \le r < b.

a=bq+r,0r<ba = bq + r, \quad 0 \le r < b

For example, 53=7×7+453 = 7 \times 7 + 4, so the quotient is 7 and the remainder is 4. A powerful exam shortcut is to reduce each large number first. If 383(mod5)38 \equiv 3 \pmod 5 and 272(mod5)27 \equiv 2 \pmod 5, then (38×27)3×2=61(mod5)(38 \times 27) \equiv 3 \times 2 = 6 \equiv 1 \pmod 5.

Unit digit questions depend on cyclicity. The last digit of powers repeats in short cycles. The cycle of powers of 2 is 2, 4, 8, 6. The cycle of powers of 3 is 3, 9, 7, 1. The cycle of powers of 7 is 7, 9, 3, 1. The cycle of powers of 9 is 9, 1.

2:2,4,8,62: 2,4,8,6
3:3,9,7,13: 3,9,7,1
4:4,64: 4,6
7:7,9,3,17: 7,9,3,1
8:8,4,2,68: 8,4,2,6
9:9,19: 9,1

So to find the unit digit of 21032^{103}, divide 103 by 4. The remainder is 3, so take the third term of the cycle. The answer is 8.

Digits 0, 1, 5, and 6 are even easier because any positive power of those numbers keeps the same last digit.

10-second shortcut: Before calculating any giant power, ask only one question: what is the cycle length of its unit digit?

This habit is the difference between a 5-second answer and a 50-second answer.

7. CUET Exam Strategy for Number System

Students often lose marks in Number System not because the concepts are too advanced, but because they start calculating before identifying the question type. In CUET UG, the first winning move is classification. Ask whether the question is about number type, parity, divisibility, factorisation, remainder, or unit digit.

If it is a classification question, compare definitions. If it is a divisibility question, check the relevant digit rule. If it is about factor count, factorise first. If it is about powers, move into modular thinking or cyclicity. This way, method selection becomes automatic.

A smart preparation sequence is also important. First build comfort with number types, negative numbers, rational vs irrational numbers, and prime vs composite logic. Next, master divisibility rules and factorisation. After that, practice remainders and unit digits. Finally, shift to mixed timed practice.

Students like Priya improve faster when they review their mistakes by category. A wrong answer in Number System usually comes from one of three causes: weak concept, wrong rule choice, or unnecessary long calculation. Labeling the cause is more useful than just reading the correct option.

Exam trap box:
1. Treating 1 as prime.
2. Forgetting that 0 is whole but not natural.
3. Mixing up factor and multiple.
4. Using digit-sum rules for divisibility by 4 or 8.
5. Ignoring cyclicity in unit digit questions.
6. Making sign mistakes while comparing negative numbers.

The right sequence for revision is simple: read one concept, solve a few examples, and then take a short timed test on that concept. That cycle produces better retention than passive reading.

With this approach, Number System stops feeling like a chapter of disconnected tricks and starts feeling like a clean set of patterns that repeat across many exam questions.

Solved Practice

30+ Solved Examples on Number System

Open only after you try the question yourself
Exam Trap: In Number System, the biggest mistake is doing long calculations too early. Before solving, ask whether the question is about classification, divisibility, prime factors, remainder, or unit digit.
Example 1. Which of the following is a whole number but not a natural number?
Natural numbers start from 1, while whole numbers include 0. So the answer is 0.
Example 2. Is -13 rational, irrational, or neither?
Any integer can be written as a fraction with denominator 1. So 13=13/1-13 = -13/1, which makes it rational.
Example 3. Is $\sqrt{49}$ irrational?
No. 49=7\sqrt{49} = 7, and 7 is an integer. Therefore it is rational.
Example 4. Which is the smallest composite number?
1 is neither prime nor composite. 2 and 3 are prime. 4 has factors 1, 2, and 4, so the answer is 4.
Example 5. Without multiplying, decide whether $135 \times 248 \times 91$ is even or odd.
Since 248 is even, the entire product is even.
Example 6. What is the parity of $27+39+84+115$?
Odd + Odd = Even, Even + Even = Even, and Even + Odd = Odd. So the final sum is odd.
Example 7. If n is odd, is $n^2$ even or odd?
Let n=2k+1n = 2k+1. Then n2=(2k+1)2=2(2k2+2k)+1n^2 = (2k+1)^2 = 2(2k^2+2k)+1, so it is always odd.
Example 8. Check whether 738 is divisible by 3 and 9.
Digit sum = 7+3+8 = 18. Since 18 is divisible by both 3 and 9, 738 is divisible by both 3 and 9.
Example 9. Is 4516 divisible by 4 and 8?
Last two digits are 16, so it is divisible by 4. Last three digits are 516, and 516 is not divisible by 8. So it is divisible by 4 only.
Example 10. Find the smallest digit that can replace x in 43x2 so that the number is divisible by 3.
The digit sum is 9+x9+x. Since 9 is already divisible by 3, x must also be divisible by 3. The smallest such digit is 0.
Example 11. Find the greatest digit that can replace y in 57y4 so that the number is divisible by 9.
The digit sum is 16+y16+y. The next multiple of 9 after 16 is 18, so y=2y=2. Therefore the answer is 2.
Example 12. Is 53724 divisible by 11?
Use the alternating-sum rule: 53+72+4=115-3+7-2+4=11. Since 11 is divisible by 11, the number is divisible by 11.
Example 13. Find the prime factorisation of 180.
180=2×90=22×45=22×32×5180 = 2 \times 90 = 2^2 \times 45 = 2^2 \times 3^2 \times 5. So the factorisation is 22×32×52^2 \times 3^2 \times 5.
Example 14. How many positive factors does 72 have?
72=23×3272 = 2^3 \times 3^2. Number of factors = (3+1)(2+1)=12(3+1)(2+1)=12. So the answer is 12.
Example 15. How many positive factors does 144 have?
144=24×32144 = 2^4 \times 3^2. Number of factors = (4+1)(2+1)=15(4+1)(2+1)=15. So the answer is 15.
Example 16. Find the sum of all factors of 18.
Factors are 1, 2, 3, 6, 9, and 18. Their sum is 39.
Example 17. Find the highest power of 2 that exactly divides 96.
96=25×396 = 2^5 \times 3, so the highest power is 25=322^5 = 32.
Example 18. How many numbers between 1 and 50 are divisible by 6?
Count multiples of 6 up to 50: 50/6=8\lfloor 50/6 \rfloor = 8. So there are 8 such numbers.
Example 19. What is the remainder when 53 is divided by 7?
53=7×7+453 = 7 \times 7 + 4, so the remainder is 4.
Example 20. What is the remainder when 248 is divided by 9?
Digit sum = 2+4+8 = 14, and 145(mod9)14 \equiv 5 \pmod 9. So the remainder is 5.
Example 21. Find the remainder when $38 \times 27$ is divided by 5.
38338 \equiv 3 and 272(mod5)27 \equiv 2 \pmod 5. Their product is 61(mod5)6 \equiv 1 \pmod 5. So the remainder is 1.
Example 22. Find the remainder when $7^5$ is divided by 6.
71(mod6)7 \equiv 1 \pmod 6, so 7515=17^5 \equiv 1^5 = 1. The remainder is 1.
Example 23. Find the unit digit of $2^{17}$.
Cycle of 2 is 2, 4, 8, 6. Since 17 leaves remainder 1 on division by 4, the unit digit is 2.
Example 24. Find the unit digit of $3^{26}$.
Cycle of 3 is 3, 9, 7, 1. Since 26 leaves remainder 2 on division by 4, the unit digit is 9.
Example 25. Find the unit digit of $7^{103}$.
Cycle of 7 is 7, 9, 3, 1. Since 103 leaves remainder 3 on division by 4, the answer is 3.
Example 26. Find the unit digit of $9^{48}$.
Cycle of 9 is 9, 1. Since 48 leaves remainder 0 on division by 2, take the last term of the cycle. The answer is 1.
Example 27. Find the unit digit of $4^{57}$.
Cycle of 4 is 4, 6. Since 57 leaves remainder 1 on division by 2, the answer is 4.
Example 28. Find the unit digit of $8^{24}$.
Cycle of 8 is 8, 4, 2, 6. Since 24 leaves remainder 0 on division by 4, the answer is the fourth term, 6.
Example 29. Find the smallest number that must be added to 278 to make it divisible by 6.
278=6×46+2278 = 6 \times 46 + 2. Add 62=46-2=4. So the answer is 4.
Example 30. Find the greatest number that must be subtracted from 278 to make it divisible by 6.
The greatest number to subtract is the remainder itself. Since 2782(mod6)278 \equiv 2 \pmod 6, subtract 2.
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Section B

The Test Zone

This topic has a separate practice route with 4 sectional sessions of 10 questions each and a full-length 40-question mock. Every question runs on a 60-second countdown so students can build concept speed and exam discipline together.

Sectional Tests

4 focused sessions on number classification, divisibility, factors, and remainder plus unit digit logic.

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Full-Length Mock

A 40-question mixed paper with timer logic, navigation, answer review, score, accuracy, and time taken.

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